3.14(6)r^2=1884

Solution for 3.14(6)r^2=1884 equation:

3.14(6)r^2=1884

We move all terms to the left:

3.14(6)r^2-(1884)=0

a = 3.146; b = 0; c = -1884;
Δ = b2-4ac
Δ = 02-4·3.146·(-1884)
Δ = 23708.256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{23708.256}}{2*3.146}=\frac{0-\sqrt{23708.256}}{6.292}
=-\frac{\sqrt{}}{6.292}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{23708.256}}{2*3.146}=\frac{0+\sqrt{23708.256}}{6.292}
=\frac{\sqrt{}}{6.292}
$